Jrheinlaender: Created page with "{{Keyword | `FSOLVE (equation, symbol, number, number )` | Numerically solve the equation for the symbol. It is assumed that the soluation lies between the lower and upper bounds given as arguments. A Newton-Raphson algorithm is used. | 3= `EQDEF 192 x^{6} - 512 sqrt{3} x^{5} + 1104 x^{4} - 384 sqrt{3} x^{3} + 132 x^{2} - 1 = 0` `EQDEF FSOLVE(@prev@, x, -0.2, -0.05)` This will find the solution `x = -0.073145130133..."`


2024-09-27T17:22:05Z
Created page with "{{Keyword | <code>FSOLVE (equation, symbol, number, number )</code> | Numerically solve the equation for the symbol. It is assumed that the soluation lies between the lower and upper bounds given as arguments. A Newton-Raphson algorithm is used. | 3= <code>EQDEF 192 x^{6} - 512 sqrt{3} x^{5} + 1104 x^{4} - 384  sqrt{3} x^{3} + 132 x^{2} - 1 = 0</code>  <code>EQDEF FSOLVE(@prev@, x, -0.2, -0.05)</code>  This will find the solution <code>x = -0.073145130133..."
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{{Keyword

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<code>FSOLVE ([[equation]], [[symbol]], [[number]], [[number]] )</code>

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Numerically solve the equation for the symbol. It is assumed that the soluation lies between the lower and upper bounds given as arguments. A Newton-Raphson algorithm is used.

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3=

<code>EQDEF 192 x^{6} - 512 sqrt{3} x^{5} + 1104 x^{4} - 384  sqrt{3} x^{3} + 132 x^{2} - 1 = 0</code>



<code>EQDEF FSOLVE(@prev@, x, -0.2, -0.05)</code>



This will find the solution <code>x = -0.073145130133813430764</code>

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4=

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5=2.3.6

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[[Category:Manipulation]]

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