Difference between revisions of "ITERATE"
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| − | Iterate an equation of the form <code>[[ | + | Iterate an equation of the form <code>[[symbol]] = [[expression]]</code> until it converges, that is, the difference between two consecutive values of the variable is less than the limit given as the third parameter. In every iteration step, the value of the variable found in the previous step is inserted into the expression on the right-hand side. |
The last parameter gives the maximum number of iterations, in case there is no convergence. | The last parameter gives the maximum number of iterations, in case there is no convergence. | ||
Revision as of 14:27, 2 July 2017
Contents
Syntax
ITERATE ( equation, expression, expression, integer )
ITERATE (equation list, expression list, expression list, integer )
Implemented in iMath since version 2.2.0 or earlier.
Explanation
Iterate an equation of the form symbol = expression until it converges, that is, the difference between two consecutive values of the variable is less than the limit given as the third parameter. In every iteration step, the value of the variable found in the previous step is inserted into the expression on the right-hand side.
The last parameter gives the maximum number of iterations, in case there is no convergence.
It is highly recommended to set the maximum number of iterations to a very low value when testing new expressions. If for some reason the expression on the right-hand side does not evaluate to a numeric value, then ITERATE can create huge symbolic expressions!
The second form of ITERATE iterates a list of equations that may depend on one another. The result is a vector. ITERATE sets the values of the variables on the left-hand side of the equations, so they can be accessed later with a VAL statement.
Example
EXDEF ITERATE(x = cos(x), 100, 0.01, 100) will start iterating with x=100. The next value of x will be sqrt(100). The result of the iteration will be approximately 0.74, since that is the solution of the equation cos(x) - x = 0
EQDEF v = ITERATE(x = cos(y);y = cos(x), 1;1, 0.01;0.01, 100) boils down to finding values of x and y where x - cos y = 0 and y - cos(x) = 0, that is x/y = cos y/cos x. The resulting value e.g. for x can be accessed as VAL(v[1]) or directly with VAL(x).
