VECTORDEF: Difference between revisions
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Declares the symbol to be a vector. This is important because vectors are non-commutative when evaluating an expression. | |||
The second form is a shortcut for the combination of <code>VECTORDEF</code> and <code>[[EQDEF]]</code>. It defines the symbol and creates an equation defining its value. | The second form is a shortcut for the combination of <code>VECTORDEF</code> and <code>[[EQDEF]]</code>. It defines the symbol and creates an equation defining its value. | ||
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<code>VECTORDEF u = STACK{ a # b # c }</code> | <code>VECTORDEF u = STACK{ a # b # c }</code> | ||
Declares two vectors <code>u</code> and <code>v</code> and assigns a value to <code>v</code>. In expression evaluation, iMath will treat the vectors as non-commutative, that is, <code>u v ≠ v u</code>. | |||
|4= | |4= | ||
[[MATRIXDEF]] | [[MATRIXDEF]] | ||
}} | }} | ||
[[Category:Definition]] | [[Category:Declaration]][[Category:Definition]] | ||
Revision as of 17:49, 21 September 2018
Syntax
VECTORDEF symbol
@label@ { options } VECTORDEF [*] symbol = expression
Implemented in iMath since version 2.2.0 or earlier.
Explanation
Declares the symbol to be a vector. This is important because vectors are non-commutative when evaluating an expression.
The second form is a shortcut for the combination of VECTORDEF and EQDEF. It defines the symbol and creates an equation defining its value.
Example
VECTORDEF v
VECTORDEF u = STACK{ a # b # c }
Declares two vectors u and v and assigns a value to v. In expression evaluation, iMath will treat the vectors as non-commutative, that is, u v ≠ v u.